ESPN gives Florida huge chance of winning vs. Samford in Week 2

According to ESPN Analytics , the Florida football team has a 97.7% chance to win against the Samford Bulldogs on Week 2 of the college football season.

That is by far the highest chance of winning a game ESPN gave the Gators this season. With the No. 1 strength of schedule in the country, that comes to no surprise.

Besides their game against Samford, the Gators are not favored in any game remaining on their schedule. Not one.

The next highest percentage they have of winning a game is against the Kentucky Wildcats and that currently sits at 45.4%

The lowest percentage that the Gators have of winning is when they play on the road in Austin, Texas, to face the Texas Longhorns . Their chance of winning that game is just 5.4%.

A long season awaits for Florida and it’s tough to see how this season can turn into something positive, as of now.

Gators chances of winning against their opponents, according to ESPN Analytics

• Home vs. Texas A&M Aggies (Sept. 14): 40.4%
• Away at Mississippi State Bulldogs (Sept. 21): 39.9%
• Home vs. UCF Knights (Oct. 5): 42.1%
• Away at Tennessee Volunteers (Oct. 12): 12.5%
• Home vs. Kentucky Wildcats (Oct. 19): 45.4%
• Neutral site vs. Georgia Bulldogs (Nov. 2): 5.7%
• Away at Texas Longhorns (Nov. 9): 5.4%
• Home vs. LSU Tigers (Nov. 16): 39.4%
• Home vs. Ole Miss Rebels (Nov. 23): 20.4%
• Away at Florida State Seminoles (Nov. 30): 36.8%

Gators Week 2 Game

Florida (0-1) will go up against the Samford Bulldogs (0-1) on Saturday at Ben Hill Griffin Stadium. Kickoff is at 7 p.m. ET and will be broadcast on SEC Network+ .

Follow us @GatorsWire on X, formerly known as Twitter, and like our page on Facebook to follow ongoing coverage of Florida Gators news, notes and opinions.